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 request 
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Joined: Mon Jun 07, 2010 3:45 pm
Posts: 5
Post request
Hello everybody
I have a problem and I hope to solve it
my question is:
Zeta[1/2,-E] that E=1-4
Zeta= Hurwithz zeta function

thanks




Mon Jun 07, 2010 4:18 pm
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Joined: Mon Jan 18, 2010 1:42 pm
Posts: 87
Post Re: request
Hello,

If you have'n yet, you could use this calculator in order to compute the hurwitz zeta function.

Good luck with that, and if you have any problems with it, please post it here, and we'll try to help you sort it out!

PS: DON'T create 2 topics for the same problem!

Cheers!


Tue Jun 08, 2010 2:45 am
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Joined: Mon Jun 07, 2010 3:45 pm
Posts: 5
Post Re: request
Hello
Thank you for your help but i need to reach Hurwithz Zeta function for following value:

zeta(1/2,-q)=? that q is 1<q<=4

Regard


Wed Jun 09, 2010 10:50 am
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Joined: Mon Jan 18, 2010 1:42 pm
Posts: 87
Post Re: request
Hi,

A far as i know, the Hurwitz Zeta Function is only defined for Re(s) > 1. With Zeta(s, q) = the Hurwitz Zeta Function.

So, i don't think it's possible to have zeta(1/2,-q).

This is from Wikipedia: "[...] It[Hurwitz Zeta Function] is formally defined for complex arguments s with Re(s)>1 and q with Re(q)>0 "

Pease check again, and come back!


Wed Jun 09, 2010 5:51 pm
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Joined: Mon Jun 07, 2010 3:45 pm
Posts: 5
Post Re: request
Dear livius
That's right but I will solve zeta(1/2,-q). It has a answer. For example zeta(1/2,-q)=
Sum[(((2 j - 1)!!*Zeta[j + 1/2])/(2^j*j!))*(q^j), {j, 1, Inf}] that 0<=q<=1


Wed Jun 09, 2010 8:13 pm
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Joined: Mon Jan 18, 2010 1:42 pm
Posts: 87
Post Re: request
Well,

I'm sorry then. I don't know what to tell you...

Sorry you could not get the help you wanted.


Wed Jun 09, 2010 10:49 pm
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Joined: Mon Jun 07, 2010 3:45 pm
Posts: 5
Post Re: request
Thank you to now


Fri Jun 11, 2010 5:31 pm
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Joined: Mon Jan 18, 2010 1:42 pm
Posts: 87
Post Re: request
No problem, come back at any time!

If we can help you, we will help you!


Fri Jun 11, 2010 11:29 pm
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