Integration Problem? : Calculus

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Integration Problem?

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Integration Problem?

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wahoo390 Joined: Sun Mar 07, 2010 6:36 pm Posts: 1	Integration Problem? If ${g}'(x)=2g(x) and g(-1)=1, then g(x)=$
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livius Joined: Mon Jan 18, 2010 1:42 pm Posts: 87	Re: Integration Problem? wahoo390 wrote: If ${g}'(x)=2g(x) and g(-1)=1, then g(x)=$ Hi, First of all, when we look at g'(x) = 2g(x) the first thing we can think of are exponentials. So, $g(x) = e^{2x+2}$ Obviously, $g'(x) = (2x+2)'e^{2x+2} = 2e^{2x+2} = 2g(x)$ and $g(-1) = e^{-2+2} = e^{0} = 1$ Hope that helps.
Tue Mar 09, 2010 11:28 am

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